1. Asked: July 1, 2025In:

    Can I Apply For JAMB With Awaiting SSCE, NECO, or NABTEB Results?

    Classgist
    Classgist Begginer

    JAMB accepts candidates awaiting results of SSCE, NECO, and NABTEB. However, Jambites are requested to update their results on the portal as soon as they are made available.

    JAMB accepts candidates awaiting results of SSCE, NECO, and NABTEB. However, Jambites are requested to update their results on the portal as soon as they are made available.

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  2. Asked: July 1, 2025In:

    How do I prepare for JAMB 2026 CBT?

    Classgist
    Classgist Begginer

    1. Come to know the JAMB Calendar Game JAMB is not all about the day of examination. It is a system - a complete calendar with most of the dates, activities, and loopholes. Be familiar with your schedule. Examine deadlines, mock exams dates, reprints of slips, verification of CBT centres, and all ofRead more

    1. Come to know the JAMB Calendar Game

    JAMB is not all about the day of examination.

    It is a system – a complete calendar with most of the dates, activities, and loopholes.

    Be familiar with your schedule.

    Examine deadlines, mock exams dates, reprints of slips, verification of CBT centres, and all of that!

    Do not miss out on anything.

    2. Enroll in a Serious CBT Centre Only

    CBT centers are not equally designed.

    Others are haphazard, inexperienced or downright fraudsters.

    It is always important to select a center that has good track record and working systems.

    3. Learn the Syllabus of the Official JAMB

    JAMB does not want to surprise you.

    They provide the syllabus to you, everything that you are going to be tested in.

    Learning: Learn that stuff as though your life depends.

    Print a copy, get cross things out, chart your advancement.

    4. Learn to Study Past Questions

    It is not just cramming.

    Know why the solutions are valid.

    Use time limit; practice real tests, and analyze with others.

    Give past questions to see trends present there!

    5. Participate in a serious WhatsApp or online group of Study.

    Motivation is killed through isolation.

    Be part of smart, focused students who give updates, mock tests and break downs.

    It is not the gossip groups. I refer to study-oriented groups.

    DURING JAMB: What No one Tells You about the Secrets

    6. Report at Your CBT Centre before 6 AM

    I do not give a care whether it is your exam at 9 AM.

    This should be done before the sun comes up.

    Why? Stress stalls or a bottleneck in verification or headlong confusion.

    Getting on time makes you relaxed and composed.

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  3. Asked: July 1, 2025In:

    How much is JAMB registration form 2026?

    Classgist
    Classgist Begginer

    The cost of the JAMB form varies each year, but it usually falls within the range of ₦4,000 to ₦6,000, including other service charges. Here is a step by step guideline on how to register:

    The cost of the JAMB form varies each year, but it usually falls within the range of ₦4,000 to ₦6,000, including other service charges. Here is a step by step guideline on how to register:

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  4. Asked: July 1, 2025In:

    When is JAMB 2026 starting?

    Classgist
    Classgist Begginer

    Most probably, the 2026 Computer Based (CBT) UTME exam will be conducted in April as it is being done in other years. The joint Admissions and Matriculation Board (JAMB) also indicated that 2026 Unified Tertiary Matriculation Examination (UTME) mock examination will take place a month before JAMB exRead more

    Most probably, the 2026 Computer Based (CBT) UTME exam will be conducted in April as it is being done in other years. The joint Admissions and Matriculation Board (JAMB) also indicated that 2026 Unified Tertiary Matriculation Examination (UTME) mock examination will take place a month before JAMB exam.

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  5. Asked: July 1, 2025In:

    Who was narrating their encounter with their teacher?

    Classgist
    Classgist Begginer

    In the novel The Life Changer by Khadija Abubakar Jalli, the author mainly tells us the story through Sade. She also recalls her experiences and relationships nature with her teacher Miss Amina who is also very wise and her influence greatly affects her life and personality. The novel revolves arounRead more

    In the novel The Life Changer by Khadija Abubakar Jalli, the author mainly tells us the story through Sade. She also recalls her experiences and relationships nature with her teacher Miss Amina who is also very wise and her influence greatly affects her life and personality. The novel revolves around the aspect of self discovery, and the aspect of discipline and the power of mentoring. The thinking of Sade can give us an idea of how Miss Amina managed to form her worldview and cope with problems.

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  6. Asked: July 1, 2025In:

    In the Life Changer Jamb Novel, Who was fond of teasing Omar?

    Classgist
    Classgist Begginer

    His Mom

    His Mom

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  7. Asked: June 29, 2025In:

    If sinθθ = K find tanθθ, 0° ≤≤ θθ ≤≤ 90°.

    Dr Ben
    Dr Ben Begginer

    You're given: sin⁡(θθ)=K\sin(θθ) = Ksin(θθ)=K and asked to find: tan⁡(θθ)\tan(θθ)tan(θθ) for 0∘≤θθ≤90∘0^\circ \leq θθ \leq 90^\circ0∘≤θθ≤90∘. Assuming the equation means: sin⁡(θθ)=K\sin(θθ) = Ksin(θθ)=K (i.e., "θθ" is treated as a single angle, so it's not a typo of sin⁡θ⋅θ\sinθ \cdot θsinθ⋅θ) ThenRead more

    You’re given:
    sin⁡(θθ)=K\sin(θθ) = Ksin(θθ)=K
    and asked to find:
    tan⁡(θθ)\tan(θθ)tan(θθ)
    for 0∘≤θθ≤90∘0^\circ \leq θθ \leq 90^\circ0∘≤θθ≤90∘.
    Assuming the equation means:

    • sin⁡(θθ)=K\sin(θθ) = Ksin(θθ)=K (i.e., “θθ” is treated as a single angle, so it’s not a typo of sin⁡θ⋅θ\sinθ \cdot θsinθ⋅θ)
    • Then we want tan⁡(θθ)\tan(θθ)tan(θθ)

    Step-by-step:

    From:
    sin⁡(θθ)=K\sin(θθ) = Ksin(θθ)=K
    Then:
    θθ=sin⁡−1(K)θθ = \sin^{-1}(K)θθ=sin−1(K)
    Then:
    tan⁡(θθ)=tan⁡(sin⁡−1(K))\tan(θθ) = \tan(\sin^{-1}(K))tan(θθ)=tan(sin−1(K))

    Identity:

    Let x=sin⁡−1(K)x = \sin^{-1}(K)x=sin−1(K). Then:
    tan⁡(x)=sin⁡(x)cos⁡(x)=K1−K2\tan(x) = \frac{\sin(x)}{\cos(x)} = \frac{K}{\sqrt{1 – K^2}}tan(x)=cos(x)sin(x)​=1−K2​K​

    (From the Pythagorean identity cos⁡(x)=1−sin⁡2(x)\cos(x) = \sqrt{1 – \sin^2(x)}cos(x)=1−sin2(x)​, valid in the range 0∘≤x≤90∘0^\circ \le x \le 90^\circ0∘≤x≤90∘).

    Final Answer:

    tan⁡(θθ)=K1−K2,for 0≤K≤1\tan(θθ) = \frac{K}{\sqrt{1 – K^2}}, \quad \text{for } 0 \le K \le 1tan(θθ)=1−K2​K​,for 0≤K≤1

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